D

To find the six trigonometric ratios of the given triangle:
Based on the triangle, we have:
- Side opposite angle \(\theta\): 4 (length OA)
- Side adjacent to angle \(\theta\): 3 (length OB)
- Hypotenuse: 5 (length AB)

1. Sine function (sin):
\( \sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{4}{5}

2. Cosine function (cos):
\( \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{3}{5}

3. Tangent function (tan):
\( \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{4}{3}

4. Cosecant function (csc):
\( \csc(\theta) = \frac{1}{\sin(\theta)} = \frac{5}{4}

5. Secant function (sec):
\( \sec(\theta) = \frac{1}{\cos(\theta)} = \frac{5}{3}

6. Cotangent function (cot):
\( \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{3}{4}

Therefore, the six trigonometric ratios are:
\(\sin(\theta) = \frac{4}{5}, \cos(\theta) = \frac{3}{5}, \tan(\theta) = \frac{4}{3}, \csc(\theta) = \frac{5}{4}, \sec(\theta) = \frac{5}{3}, \text{and } \cot(\theta) = \frac{3}{4}.